[BLML] Scoring 2 and 3 Fouled Boards

Sven Pran sven at svenpran.net
Sun Mar 6 16:41:55 CET 2016


My example was for 13 tables Mitchell or 7 tables Howell. In either case each board will be scheduled for play 13 times with a top score of 24.  

 

The Aussie regulation should specify the required number of scores in a separate group for the application of Neuberg as a percentage of the total number of scores in a complete (undisturbed) group. The top score itself  is only confusing. 

 

As here: How can a top score of 50 in any way be relevant with my example? (They don’t play the same board twice!)

Fra: blml-bounces at rtflb.org [mailto:blml-bounces at rtflb.org] På vegne av Petrus Schuster OSB
Sendt: 6. mars 2016 13:36
Til: Bridge Laws Mailing List
Emne: Re: [BLML] Scoring 2 and 3 Fouled Boards

 

On Sat, 05 Mar 2016 22:18:50 +0100, Sven Pran <sven at svenpran.net> wrote:

Well, that clarifies one point – but not what it means that a fouled board has been played less than 10 percent of the top score. Fouled board must be scored separately from the normal boards so within a group of at least two equal fouled boards their scores will be from (and including) 0 to (and including) 100 percent of the top score within that group.

 

 

10% of the normal top on a board in this session. So in your example, 26 results give a top of 50; 10% of that means less than 5 rounds. 30% of 13 rounds is 3.9 rounds. Both conditions have to be met, so there will be artificial scores (60-50, 50-50 and 50-60) if the fouled version has been played no more than three times.

 

Fra: blml-bounces at rtflb.org [mailto:blml-bounces at rtflb.org] På vegne av Petrus Schuster OSB
Sendt: 5. mars 2016 20:45
Til: Bridge Laws Mailing List
Emne: Re: [BLML] Scoring 2 and 3 Fouled Boards

 

On Wed, 02 Mar 2016 10:59:22 +0100, Sven Pran < <mailto:sven at svenpran.net> sven at svenpran.net> wrote:

Sorry, but this doesn’t make sense to me:

How do you calculate whether the fouled version of a board has been played more or less than 10 percent of the top score?

 

And anyway, say that you have a 13 table Mitchell or a 7 table Howell event. Each board should then be played 13 times, however the fouled version was played 6 times. Neither version was played less than 30% of the rounds, do you really end up with 13 artificial adjusted scores on that board instead of scoring two groups with Neuberg?  

 

Fra: blml-bounces at rtflb.org [mailto:blml-bounces at rtflb.org] På vegne av Petrus Schuster OSB
[…]

 

The Austrian Regulations use Neuberg, when  the fouled version of the board had been played both less than 10 percent of the top score and less than 30 percent of the rounds of the session. Otherwise, artificial adjusted scores are awarded.

 

Petrus

 

 

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sorry ... read "unless" instead of "when".

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